35 results found for "250 ml" in Class 10.
यदि सरल भिन्न का हर (250) है, तो उसका दशमलव प्रसार कितने स्थानों पर समाप्त होगा?
If the denominator of a fraction in lowest form is (250), after how many places will its decimal expansion terminate?
#decimal-places
#denominator-250
#terminating
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
\(250=2\times5^3\).
Step 2
Why this answer is correct
The larger exponent is (3), so the decimal ends after (3) places.
Step 3
Exam Tip
Exam tip: Thinking of converting (250) to (1000) gives the same answer. चरण 1: \(250=2\times5^3\) है। चरण 2: बड़ी घात (3) है, इसलिए दशमलव (3) स्थानों पर समाप्त होगा। चरण 3: परीक्षा सुझाव: हर (250) को (1000) बनाने की सोच से भी यही उत्तर मिलता है।
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\(\frac{9}{250}\) का दशमलव रूप कौन-सा है?
Which is the decimal form of \(\frac{9}{250}\)?
#real numbers
#fraction to decimal
#denominator 250
#class 10
A (0.036)
B (0.36)
C (0.0036)
D (3.6)
Explanation opens after your attempt
Correct Answer
A. (0.036)
Step 1
Concept
Multiply (250) by (4) to make (1000).
Step 2
Why this answer is correct
\(\frac{9}{250}=\frac{36}{1000}=0.036\).
Step 3
Exam Tip
Pay attention to the correct position of zeros in decimals. चरण 1: (250) को (1000) बनाने के लिए (4) से गुणा करें। चरण 2: \(\frac{9}{250}=\frac{36}{1000}=0.036\) है। चरण 3: दशमलव में शून्य की सही स्थिति पर ध्यान दें।
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सरल रूप में किसी भिन्न का भाजक (250) है। उसका दशमलव विस्तार अधिकतम कितने स्थानों के बाद समाप्त होगा?
If the denominator of a fraction in lowest form is (250), after at most how many decimal places will its decimal expansion terminate?
#real numbers
#decimal places
#denominator 250
#class 10
A एक / One
B दो / Two
C तीन / Three
D चार / Four
Explanation opens after your attempt
Correct Answer
C. तीन / Three
Step 1
Concept
\(250=2\times5^3\).
Step 2
Why this answer is correct
The larger exponent is (3), so the decimal terminates within three places.
Step 3
Exam Tip
Comparing exponents saves time in exams. चरण 1: \(250=2\times5^3\) है। चरण 2: बड़ी घात (3) है, इसलिए दशमलव अधिकतम तीन स्थानों पर समाप्त होगा। चरण 3: घातों की तुलना करने की आदत परीक्षा में समय बचाती है।
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(250) का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of (250)?
#real-numbers
#prime-factorisation
#250
A \(2 \times 5^3\)
B \(2^2 \times 5^2\)
C \(2 \times 5^2\)
D \(2^3 \times 5\)
Explanation opens after your attempt
Correct Answer
A. \(2 \times 5^3\)
Step 1
Concept
Write \(250=25 \times 10\).
Step 2
Why this answer is correct
\(25=5^2\) and \(10=2 \times 5\), so \(250=2 \times 5^3\).
Step 3
Exam Tip
Combine repeated (5) factors into a power. चरण 1: \(250=25 \times 10\) लिखें। चरण 2: \(25=5^2\) और \(10=2 \times 5\), इसलिए \(250=2 \times 5^3\)। चरण 3: समान (5) गुणनखंडों को जोड़कर घात बनाएं।
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एक ऐप की आय पहले दिन (1200) रुपये है और हर अगले दिन (250) रुपये बढ़ती है। (10) दिनों की कुल आय कितनी होगी?
An app earns (1200) rupees on the first day and the income increases by (250) rupees each next day. What is the total income in (10) days?
#ap
#word-problem
#income
#total
A (23000)
B (23250)
C (23500)
D (23750)
Explanation opens after your attempt
Correct Answer
B. (23250)
Step 1
Concept
The income is \(1200,1450,1700,\ldots\) and \(S_{10}=23250\). Exam tip: add daily income as AP terms.
Step 2
Why this answer is correct
The correct answer is B. (23250). The income is \(1200,1450,1700,\ldots\) and \(S_{10}=23250\). Exam tip: add daily income as AP terms.
Step 3
Exam Tip
आय \(1200,1450,1700,\ldots\) है और \(S_{10}=23250\)। परीक्षा में दैनिक आय को ए.पी. के पदों की तरह जोड़ें।
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एक बचत योजना में पहले महीने (250) रुपये जमा होते हैं और (20) महीनों की कुल बचत (19300) रुपये है। यदि हर महीने बचत समान रूप से बढ़ती है तो मासिक वृद्धि कितनी है?
In a saving plan (250) rupees are deposited in the first month and the total saving in (20) months is (19300) rupees. If the saving increases equally every month, what is the monthly increase?
#ap
#word-problem
#saving
#difference
A (70)
B (75)
C (80)
D (85)
Explanation opens after your attempt
Step 1
Concept
Using \(S_{20}=19300\) and (a=250) gives (d=75). Exam tip: find the common difference from total and first term.
Step 2
Why this answer is correct
The correct answer is B. (75). Using \(S_{20}=19300\) and (a=250) gives (d=75). Exam tip: find the common difference from total and first term.
Step 3
Exam Tip
\(S_{20}=19300\) और (a=250) रखने पर (d=75) मिलता है। परीक्षा में कुल और प्रथम पद से सार्व अंतर निकालें।
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एक दान अभियान में पहले दिन (250) रुपये मिले और हर अगले दिन (125) रुपये अधिक मिले। कुल (9625) रुपये जमा होने में कितने दिन लगेंगे?
In a donation campaign (250) rupees are received on the first day and (125) rupees more each next day. How many days will it take to collect (9625) rupees?
#ap
#word-problem
#donation
#target
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
The donation amounts are \(250,375,500,\ldots\) and \(S_n=9625\) gives (n=11). Exam tip: form an \(S_n\) equation for the target total.
Step 2
Why this answer is correct
The correct answer is C. (11). The donation amounts are \(250,375,500,\ldots\) and \(S_n=9625\) gives (n=11). Exam tip: form an \(S_n\) equation for the target total.
Step 3
Exam Tip
दान राशि \(250,375,500,\ldots\) है और \(S_n=9625\) से (n=11)। परीक्षा में लक्ष्य कुल राशि के लिए \(S_n\) का समीकरण बनाएं।
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एक कोर्स की फीस पहले महीने (250) रुपये है और हर अगले महीने (75) रुपये बढ़ती है। किस महीने फीस (1075) रुपये होगी?
A course fee is (250) rupees in the first month and increases by (75) rupees each next month. In which month will the fee be (1075) rupees?
#ap
#word-problem
#fee
#target-month
A (11)
B (12)
C (13)
D (14)
Explanation opens after your attempt
Step 1
Concept
From (250+(n-1)75=1075), (n=12). Exam tip: set the required amount equal to \(a_n\).
Step 2
Why this answer is correct
The correct answer is B. (12). From (250+(n-1)75=1075), (n=12). Exam tip: set the required amount equal to \(a_n\).
Step 3
Exam Tip
(250+(n-1)75=1075) से (n=12) मिलता है। परीक्षा में वांछित राशि को \(a_n\) के बराबर रखें।
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एक ऐप की आय पहले दिन (250) रुपये है और हर अगले दिन (35) रुपये बढ़ती है। (11)वें दिन आय कितनी होगी?
An app earns (250) rupees on the first day and the income increases by (35) rupees each next day. What will be the income on the (11)th day?
#ap
#word-problem
#income
#nth-day
A (565)
B (600)
C (635)
D (670)
Explanation opens after your attempt
Step 1
Concept
The income is \(250,285,320,\ldots\) and \(a_{11}=600\). Exam tip: use the (n)th term for a particular day.
Step 2
Why this answer is correct
The correct answer is B. (600). The income is \(250,285,320,\ldots\) and \(a_{11}=600\). Exam tip: use the (n)th term for a particular day.
Step 3
Exam Tip
आय \(250,285,320,\ldots\) है और \(a_{11}=600\)। परीक्षा में किसी विशेष दिन के लिए (n)वाँ पद लगाएं।
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एक फंड में पहले सप्ताह (250) रुपये जमा हुए और हर अगले सप्ताह (40) रुपये अधिक जमा हुए। (14) सप्ताहों में कुल कितनी राशि जमा होगी?
A fund receives (250) rupees in the first week and (40) rupees more each next week. What is the total amount in (14) weeks?
#ap
#word-problem
#fund
#total
A (6940)
B (7040)
C (7140)
D (7240)
Explanation opens after your attempt
Step 1
Concept
The deposits are \(250,290,330,\ldots\) and \(S_{14}=7140\). Exam tip: treat weekly deposits as AP terms.
Step 2
Why this answer is correct
The correct answer is C. (7140). The deposits are \(250,290,330,\ldots\) and \(S_{14}=7140\). Exam tip: treat weekly deposits as AP terms.
Step 3
Exam Tip
जमा राशि \(250,290,330,\ldots\) है और \(S_{14}=7140\)। परीक्षा में साप्ताहिक जमा को ए.पी. के पद मानें।
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(50) और (250) के बीच उन संख्याओं का योग कितना है जो (4) से विभाज्य हैं लेकिन (8) से विभाज्य नहीं हैं?
What is the sum of numbers between (50) and (250) that are divisible by (4) but not divisible by (8)?
#ap
#conditional-divisibility
#expert
A (3600)
B (3700)
C (3800)
D (3900)
Explanation opens after your attempt
Step 1
Concept
The numbers are \(52,60,\ldots,244\), and there are (25) terms. Exam tip: convert the condition into the correct AP.
Step 2
Why this answer is correct
The correct answer is B. (3700). The numbers are \(52,60,\ldots,244\), and there are (25) terms. Exam tip: convert the condition into the correct AP.
Step 3
Exam Tip
संख्याएँ \(52,60,\ldots,244\) हैं और कुल (25) पद हैं। परीक्षा में शर्त को सही समान्तर श्रेणी में बदलें।
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समांतर श्रेढ़ी \(250,238,226,\ldots\) के पहले (30) पदों का योग ज्ञात कीजिए।
Find the sum of the first (30) terms of the AP \(250,238,226,\ldots\).
#decreasing sequence
#last term
#sum
A (2200)
B (2240)
C (2320)
D (2280)
Explanation opens after your attempt
Step 1
Concept
The last term is (-98), and \(S_{30}=2280\). Once the last term is found, (S_n=\frac{n}{2}(a+l)) is faster.
Step 2
Why this answer is correct
The correct answer is D. (2280). The last term is (-98), and \(S_{30}=2280\). Once the last term is found, (S_n=\frac{n}{2}(a+l)) is faster.
Step 3
Exam Tip
अंतिम पद (-98) है और \(S_{30}=2280\) है। अंतिम पद मिल जाए तो (S_n=\frac{n}{2}(a+l)) तेज रहता है।
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(250) से (1000) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (12) से विभाज्य हैं लेकिन (18) से विभाज्य नहीं हैं।
Find the sum of all numbers from (250) to (1000) that are divisible by (12) but not by (18).
#lcm
#divisible not divisible
#ap
A (26460)
B (26280)
C (26640)
D (26820)
Explanation opens after your attempt
Correct Answer
A. (26460)
Step 1
Concept
Subtracting the sum of multiples of (36) from the sum of multiples of (12) gives (26460). Use the least common multiple to remove overlap.
Step 2
Why this answer is correct
The correct answer is A. (26460). Subtracting the sum of multiples of (36) from the sum of multiples of (12) gives (26460). Use the least common multiple to remove overlap.
Step 3
Exam Tip
(12) के गुणजों के योग से (36) के गुणजों का योग घटाने पर (26460) मिलता है। overlap हटाने के लिए लघुत्तम समापवर्त्य लें।
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(50) से (250) तक (7) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।
Find the sum of all numbers divisible by (7) from (50) to (250).
#multiples
#closed interval
#ap
A (4172)
B (4196)
C (4214)
D (4242)
Explanation opens after your attempt
Step 1
Concept
The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.
Step 2
Why this answer is correct
The correct answer is C. (4214). The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.
Step 3
Exam Tip
श्रेढ़ी \(56,63,\ldots,245\) है जिसमें (28) पद हैं और योग (4214) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें।
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किसी समांतर श्रेढ़ी में \(S_{10}=250\) और \(S_{20}=900\) है। \(S_{30}\) का मान ज्ञात कीजिए।
In an AP, \(S_{10}=250\) and \(S_{20}=900\). Find the value of \(S_{30}\).
#two sums
#find sn
#ap
A (1950)
B (1900)
C (2000)
D (2050)
Explanation opens after your attempt
Step 1
Concept
The two sums give (a=7) and (d=4), so \(S_{30}=1950\). When two partial sums are given, find (a,d) first.
Step 2
Why this answer is correct
The correct answer is A. (1950). The two sums give (a=7) and (d=4), so \(S_{30}=1950\). When two partial sums are given, find (a,d) first.
Step 3
Exam Tip
दोनों योगों से (a=7) और (d=4) मिलते हैं, इसलिए \(S_{30}=1950\)। दो partial sums दिए हों तो पहले (a,d) निकालें।
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एक बचत योजना में पहले महीने (1500) रुपये और हर अगले महीने (250) रुपये अधिक जमा किए जाते हैं। (18) महीनों में कुल जमा राशि कितनी होगी?
In a saving plan, (1500) rupees are deposited in the first month and (250) rupees more every next month. What is the total deposit in (18) months?
#savings
#word problem
#ap sum
A (65250)
B (65750)
C (64750)
D (66250)
Explanation opens after your attempt
Correct Answer
A. (65250)
Step 1
Concept
This is an AP with (a=1500), (d=250), (n=18), and the total is (65250). In word problems, treat each amount as a term.
Step 2
Why this answer is correct
The correct answer is A. (65250). This is an AP with (a=1500), (d=250), (n=18), and the total is (65250). In word problems, treat each amount as a term.
Step 3
Exam Tip
यह (a=1500), (d=250), (n=18) वाली श्रेढ़ी है और कुल योग (65250) है। शब्द-प्रश्न में राशि को पद मानें।
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यदि \(S_{10}=250\) और \(S_9=207\), तो (10)वाँ पद क्या है?
If \(S_{10}=250\) and \(S_9=207\), what is the (10)th term?
#nth term from sum
#ap
#class 10
A (40)
B (42)
C (43)
D (45)
Explanation opens after your attempt
Step 1
Concept
\(a_{10}=S_{10}-S_9=43\). The difference of consecutive sums gives the corresponding term.
Step 2
Why this answer is correct
The correct answer is C. (43). \(a_{10}=S_{10}-S_9=43\). The difference of consecutive sums gives the corresponding term.
Step 3
Exam Tip
\(a_{10}=S_{10}-S_9=43\)। लगातार योगों का अंतर संबंधित पद देता है।
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(50) और (250) के बीच (15) से विभाज्य संख्याओं का योग ज्ञात कीजिए।
Find the sum of the numbers divisible by (15) between (50) and (250).
#divisibility
#range
#ap_sum
A (1920)
B (1930)
C (1940)
D (1950)
Explanation opens after your attempt
Step 1
Concept
The numbers are \(60,75,\ldots,240\), and there are (13) terms, so the sum is (1950). Make the correct sequence by checking the limits.
Step 2
Why this answer is correct
The correct answer is D. (1950). The numbers are \(60,75,\ldots,240\), and there are (13) terms, so the sum is (1950). Make the correct sequence by checking the limits.
Step 3
Exam Tip
संख्याएँ \(60,75,\ldots,240\) हैं और (13) पद हैं, इसलिए योग (1950) है। सीमा को देखकर सही श्रेणी बनाएँ।
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(100) से (250) के बीच (8) से विभाज्य संख्याओं का योग ज्ञात कीजिए।
Find the sum of the numbers divisible by (8) between (100) and (250).
#divisibility
#range
#ap_sum
A (3192)
B (3292)
C (3392)
D (3492)
Explanation opens after your attempt
Step 1
Concept
The numbers are \(104,112,\ldots,248\), and there are (19) terms, so the sum is (3192). In boundary questions, choose the first and last terms carefully.
Step 2
Why this answer is correct
The correct answer is A. (3192). The numbers are \(104,112,\ldots,248\), and there are (19) terms, so the sum is (3192). In boundary questions, choose the first and last terms carefully.
Step 3
Exam Tip
संख्याएँ \(104,112,\ldots,248\) हैं और (19) पद हैं, इसलिए योग (3192) है। सीमा वाले प्रश्न में पहला और अंतिम पद सावधानी से चुनें।
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एक बचत योजना में हर महीने जमा राशि \(200,250,300,\ldots\) रुपये है। पहले (8) महीनों की कुल राशि कितनी होगी?
In a savings plan, the monthly deposit is \(200,250,300,\ldots\) rupees. What is the total amount for the first (8) months?
#word_problem
#savings
#ap_sum
A (2900)
B (3000)
C (3100)
D (3200)
Explanation opens after your attempt
Step 1
Concept
Here (a=200), (d=50), and (n=8), so the total is (3000) rupees. In money questions, keep the unit in mind.
Step 2
Why this answer is correct
The correct answer is B. (3000). Here (a=200), (d=50), and (n=8), so the total is (3000) rupees. In money questions, keep the unit in mind.
Step 3
Exam Tip
यहाँ (a=200), (d=50), (n=8) है, इसलिए कुल (3000) रुपये होंगे। राशि वाले प्रश्न में इकाई भी लिखें।
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यदि \(a_{20}=a+19d=250\) और \(a_{56}=a+55d=862\) है, तो \(a_{92}\) क्या होगा?
If \(a_{20}=a+19d=250\) and \(a_{56}=a+55d=862\), what is \(a_{92}\)?
#ap expert equation
A (1464)
B (1474)
C (1484)
D (1494)
Explanation opens after your attempt
Step 1
Concept
(36d=612), so (d=17). \(a_{92}=862+36\times17=1474\).
Step 2
Why this answer is correct
The correct answer is B. (1474). (36d=612), so (d=17). \(a_{92}=862+36\times17=1474\).
Step 3
Exam Tip
(36d=612), इसलिए (d=17)। \(a_{92}=862+36\times17=1474\)।
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(250) से बड़े (13) के गुणजों की AP \(260,273,286,\ldots\) है। इसका (22)वां पद क्या होगा?
The AP of multiples of (13) greater than (250) is \(260,273,286,\ldots\). What is its (22)nd term?
#ap-multiple-nth-hard
A (520)
B (533)
C (546)
D (559)
Explanation opens after your attempt
Step 1
Concept
Here (a=260) and (d=13). \(a_{22}=260+21\times13=533\).
Step 2
Why this answer is correct
The correct answer is B. (533). Here (a=260) and (d=13). \(a_{22}=260+21\times13=533\).
Step 3
Exam Tip
यहां (a=260) और (d=13)। \(a_{22}=260+21\times13=533\)।
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समान्तर श्रेणी \(13,21,29,\ldots\) में (250) से छोटा सबसे बड़ा पद क्या है?
In the AP \(13,21,29,\ldots\), what is the greatest term less than (250)?
#ap greatest-less-than nth-term class10
A (237)
B (241)
C (245)
D (249)
Explanation opens after your attempt
Step 1
Concept
The terms are of the form (13+8(n-1)) and the greatest such term less than (250) is (245). In limit questions check the next term too.
Step 2
Why this answer is correct
The correct answer is C. (245). The terms are of the form (13+8(n-1)) and the greatest such term less than (250) is (245). In limit questions check the next term too.
Step 3
Exam Tip
पद (13+8(n-1)) के रूप में हैं और (250) से कम सबसे बड़ा ऐसा पद (245) है। सीमा वाले प्रश्न में अगले पद से भी जांच करें।
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यदि बचत राशि हर सप्ताह (50) रुपये बढ़ती है और राशियां \(100,150,200,250,\ldots\) हैं तो सार्व अंतर क्या है?
If savings increase by (50) rupees every week and the amounts are \(100,150,200,250,\ldots\), what is the common difference?
#ap
#word problem
#savings
#common difference
A (50)
B (100)
C (150)
D (250)
Explanation opens after your attempt
Step 1
Concept
The consecutive difference is (150-100=50). In real-life questions the equal increase is (d).
Step 2
Why this answer is correct
The correct answer is A. (50). The consecutive difference is (150-100=50). In real-life questions the equal increase is (d).
Step 3
Exam Tip
क्रमागत अंतर (150-100=50) है। वास्तविक जीवन के प्रश्नों में समान बढ़ोतरी ही (d) होती है।
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दो टिकटों के दामों के लिए (4x+3y=120) और (8x+6y=250) समीकरण बने। यह प्रणाली कैसी है?
For prices of two tickets, the equations (4x+3y=120) and (8x+6y=250) are formed. What type of system is this?
#linear equations
#word problem
#inconsistent
A संगत और स्वतंत्र / Consistent and independent
B संगत और आश्रित / Consistent and dependent
C असंगत / Inconsistent
D अनंत हल वाली / With infinitely many solutions
Explanation opens after your attempt
Correct Answer
C. असंगत / Inconsistent
Step 1
Concept
The first two ratios are equal but (120/250) is different. Therefore, the system is inconsistent.
Step 2
Why this answer is correct
The correct answer is C. असंगत / Inconsistent. The first two ratios are equal but (120/250) is different. Therefore, the system is inconsistent.
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं लेकिन (120/250) अलग है। इसलिए प्रणाली असंगत है।
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यदि (4a+3b=276) और (2a+5b=250), तो (a) का मान क्या है?
If (4a+3b=276) and (2a+5b=250), what is the value of (a)?
#linear equations
#word pattern
#elimination
#hard
#class 10
A (a=35)
B (a=40)
C (a=50)
D (a=45)
Explanation opens after your attempt
Step 1
Concept
Multiply the second equation by (2) and subtract the first. This gives (b=32), then (a=45).
Step 2
Why this answer is correct
The correct answer is D. (a=45). Multiply the second equation by (2) and subtract the first. This gives (b=32), then (a=45).
Step 3
Exam Tip
दूसरे समीकरण को (2) से गुणा कर पहले से घटाएं। (b=32) और फिर (a=45) मिलता है।
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दो धनात्मक संख्याओं के वर्गों का योग (250) है और उनमें अंतर (4) है। बड़ी संख्या क्या है?
The sum of squares of two positive numbers is (250) and their difference is (4). What is the larger number?
#quadratic-equations
#word-problems
#sum-of-squares
A (13)
B (9)
C (11)
D (15)
Explanation opens after your attempt
Step 1
Concept
If the smaller number is (x), the larger is (x+4). From (x-2 +(x+4)2 =250), (x=9), so the larger number is (13).
Step 2
Why this answer is correct
The correct answer is A. (13). If the smaller number is (x), the larger is (x+4). From (x-2 +(x+4)2 =250), (x=9), so the larger number is (13).
Step 3
Exam Tip
यदि छोटी संख्या (x) है, तो बड़ी (x+4) है। (x-2 +(x+4)2 =250) से (x=9), इसलिए बड़ी संख्या (13) है।
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दो संख्याओं का योग (22) है और उनके वर्गों का योग (250) है। बड़ी संख्या क्या है?
The sum of two numbers is (22) and the sum of their squares is (250). What is the larger number?
#quadratic-equations
#word-problems
#sum-of-squares
A (15)
B (7)
C (11)
D (13)
Explanation opens after your attempt
Step 1
Concept
If one number is (x), the other is (22-x). From (x-2 +(22-x)2 =250), the numbers are (15) and (7).
Step 2
Why this answer is correct
The correct answer is A. (15). If one number is (x), the other is (22-x). From (x-2 +(22-x)2 =250), the numbers are (15) and (7).
Step 3
Exam Tip
यदि एक संख्या (x) है, तो दूसरी (22-x) होगी। (x-2 +(22-x)2 =250) से संख्याएँ (15) और (7) हैं।
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एक आयताकार नोटिस बोर्ड की लंबाई चौड़ाई से (15) सेमी अधिक है और क्षेत्रफल (250) वर्ग सेमी है। चौड़ाई क्या है?
A rectangular notice board has length (15) cm more than its breadth and area (250) square cm. What is its breadth?
#quadratic equations
#rectangle
#notice board
A (8) सेमी / (8) cm
B (10) सेमी / (10) cm
C (12) सेमी / (12) cm
D (15) सेमी / (15) cm
Explanation opens after your attempt
Correct Answer
B. (10) सेमी / (10) cm
Step 1
Concept
(x(x+15)=250) gives (x=10). Check at the end using \(10 \times 25=250\).
Step 2
Why this answer is correct
The correct answer is B. (10) सेमी / (10) cm. (x(x+15)=250) gives (x=10). Check at the end using \(10 \times 25=250\).
Step 3
Exam Tip
(x(x+15)=250) से (x=10) है। अंत में \(10 \times 25=250\) से जाँच करें।
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\(\frac{1}{96}\), \(\frac{1}{175}\), \(\frac{1}{224}\), \(\frac{1}{250}\) में किसमें आवर्ती भाग से पहले सबसे अधिक अनावर्ती अंक होंगे?
Among \(\frac{1}{96}\), \(\frac{1}{175}\), \(\frac{1}{224}\), and \(\frac{1}{250}\), which has the most non-repeating digits before the recurring part?
#preperiod
#comparison
#recurring-decimal
#advanced
A \(\frac{1}{96}\)
B \(\frac{1}{175}\)
C \(\frac{1}{224}\)
D \(\frac{1}{250}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{1}{224}\)
Step 1
Concept
\(224=2^5\cdot 7\), so (5) non-repeating digits appear before the recurring part. For comparison, check the larger power of (2) and (5).
Step 2
Why this answer is correct
The correct answer is C. \(\frac{1}{224}\). \(224=2^5\cdot 7\), so (5) non-repeating digits appear before the recurring part. For comparison, check the larger power of (2) and (5).
Step 3
Exam Tip
\(224=2^5\cdot 7\) है इसलिए आवर्ती भाग से पहले (5) अनावर्ती अंक आएँगे। तुलना में (2) और (5) की बड़ी घात देखें।
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\(\frac{31}{250}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?
After how many places will the decimal expansion of \(\frac{31}{250}\) terminate?
#terminating decimal
#decimal places
#real numbers
A (2) स्थान / (2) places
B (3) स्थान / (3) places
C (4) स्थान / (4) places
D असमाप्त रहेगा / It will not terminate
Explanation opens after your attempt
Correct Answer
B. (3) स्थान / (3) places
Step 1
Concept
\(250=2\times5^3\).
Step 2
Why this answer is correct
The denominator contains only (2) and (5).
Step 3
Exam Tip
The larger exponent is (3), so the decimal terminates after (3) places. चरण 1: \(250=2\times5^3\) है। चरण 2: हर में केवल (2) और (5) हैं। चरण 3: बड़ी घात (3) है, इसलिए दशमलव (3) स्थानों पर समाप्त होगा।
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कौन-सी सबसे छोटी संख्या (121), (144) और (250) से पूरी तरह विभाजित होगी?
What is the smallest number exactly divisible by (121), (144), and (250)?
#real-numbers
#lcm
#divisibility
A (217800)
B (1089000)
C (1452000)
D (2178000)
Explanation opens after your attempt
Correct Answer
D. (2178000)
Step 1
Concept
The smallest number exactly divisible by all is the LCM.
Step 2
Why this answer is correct
\(121=11^2\), \(144=2^4\times3^2\), and \(250=2\times5^3\), so LCM \(=2^4\times3^2\times5^3\times11^2=2178000\).
Step 3
Exam Tip
Multiply the highest powers carefully. चरण 1: सबसे छोटी समान विभाज्य संख्या लघुत्तम समापवर्त्य होती है। चरण 2: \(121=11^2\), \(144=2^4\times3^2\), \(250=2\times5^3\), इसलिए लघुत्तम समापवर्त्य \(2^4\times3^2\times5^3\times11^2=2178000\) है। चरण 3: बड़ी घातों का गुणन सावधानी से करें।
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संख्या 250 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 250?
#prime-factorisation
#real-numbers
#class-10
A \(2\times5^3\)
B \(2^2\times5^2\)
C \(5^4\)
D \(25\times10\)
Explanation opens after your attempt
Correct Answer
A. \(2\times5^3\)
Step 1
Concept
Write \(250=2\times125\).
Step 2
Why this answer is correct
\(125=5^3\), so \(250=2\times5^3\).
Step 3
Exam Tip
25 and 10 are composite, so do not keep them in the final prime form. चरण 1: \(250=2\times125\) लिखें। चरण 2: \(125=5^3\), इसलिए \(250=2\times5^3\)। चरण 3: 25 और 10 संयुक्त हैं, इसलिए अंतिम अभाज्य रूप में न रखें।
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उसी स्थिति में (a=250), (b=37) के लिए शेषफल (r) क्या होगा?
In the same situation, for (a=250) and (b=37), what is the remainder (r)?
#real-numbers
#remainder
#calculation
A (18)
B (28)
C (37)
D (43)
Explanation opens after your attempt
Step 1
Concept
From the previous calculation, (q=6).
Step 2
Why this answer is correct
\(r=250-37 \times 6=250-222=28\).
Step 3
Exam Tip
After getting the answer, check that (28<37). चरण 1: पिछले हिसाब से (q=6) है। चरण 2: \(r=250-37 \times 6=250-222=28\)। चरण 3: उत्तर के बाद जाँचें कि (28<37) है।
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(a=250), (b=37) के लिए भागफल (q) क्या होगा?
For (a=250) and (b=37), what is the quotient (q)?
#real-numbers
#quotient
#division-lemma
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(37 \times 6=222\) and \(37 \times 7=259\).
Step 2
Why this answer is correct
(259) is greater than (250), so the quotient is (6).
Step 3
Exam Tip
Checking the next multiple helps choose the correct quotient. चरण 1: \(37 \times 6=222\) और \(37 \times 7=259\)। चरण 2: (259) (250) से बड़ा है, इसलिए भागफल (6) होगा। चरण 3: अगला गुणज जाँचने से भागफल सही चुना जाता है।
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