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8 results found for "103-degrees" in Class 10.

Question Expert Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

एक समान्तर श्रेणी का प्रथम पद (3) है और अंतिम पद (103) है। यदि योग (901) है तो पदों की संख्या कितनी है?

The first term of an arithmetic progression is (3) and the last term is (103). If the sum is (901), how many terms are there?

Explanation opens after your attempt
Correct Answer

B. (17)

Step 1

Concept

From (901=\frac{n}{2}(3+103)), (n=17). Exam tip: when first and last terms are known, use (S_n=\frac{n}{2}(a+l)).

Step 2

Why this answer is correct

The correct answer is B. (17). From (901=\frac{n}{2}(3+103)), (n=17). Exam tip: when first and last terms are known, use (S_n=\frac{n}{2}(a+l)).

Step 3

Exam Tip

(901=\frac{n}{2}(3+103)) से (n=17) है। परीक्षा में प्रथम और अंतिम पद मिलें तो (S_n=\frac{n}{2}(a+l)) लगाएं।

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Question Hard Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 64

यदि किसी समान्तर श्रेणी में \(a_7=31\) और \(a_{19}=103\) है तो \(a_{34}\) का मान क्या होगा?

If in an AP \(a_7=31\) and \(a_{19}=103\), what is the value of \(a_{34}\)?

Explanation opens after your attempt
Correct Answer

B. (193)

Step 1

Concept

\(d=\frac{103-31}{19-7}=6\), so \(a_{34}=103+15\times6=193\). First find (d), then move forward from the nearer term.

Step 2

Why this answer is correct

The correct answer is B. (193). \(d=\frac{103-31}{19-7}=6\), so \(a_{34}=103+15\times6=193\). First find (d), then move forward from the nearer term.

Step 3

Exam Tip

\(d=\frac{103-31}{19-7}=6\) इसलिए \(a_{34}=103+15\times6=193\)। पहले (d) निकालकर निकट पद से आगे बढ़ें।

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Question Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि \(a_8=47\) और \(a_{15}=103\) है तो \(a_{22}\) क्या होगा?

If \(a_8=47\) and \(a_{15}=103\), what is \(a_{22}\)?

Explanation opens after your attempt
Correct Answer

C. (159)

Step 1

Concept

\(d=\frac{103-47}{15-8}=8\) so \(a_{22}=103+7\times8=159\). Add equal term gaps for equally spaced positions.

Step 2

Why this answer is correct

The correct answer is C. (159). \(d=\frac{103-47}{15-8}=8\) so \(a_{22}=103+7\times8=159\). Add equal term gaps for equally spaced positions.

Step 3

Exam Tip

\(d=\frac{103-47}{15-8}=8\) इसलिए \(a_{22}=103+7\times8=159\)। बराबर दूरी वाले पदों में समान अंतर जोड़ें।

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Question Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 64

किसी समान्तर श्रेणी में (a=5), (d=7) और \(a_n=103\) है। (n) का मान क्या है?

In an AP, (a=5), (d=7), and \(a_n=103\). What is the value of (n)?

Explanation opens after your attempt
Correct Answer

C. (15)

Step 1

Concept

From (103=5+(n-1)7), (98=7(n-1)), so (n=15). When finding the term number, remember to add (1) at the end.

Step 2

Why this answer is correct

The correct answer is C. (15). From (103=5+(n-1)7), (98=7(n-1)), so (n=15). When finding the term number, remember to add (1) at the end.

Step 3

Exam Tip

(103=5+(n-1)7) से (98=7(n-1)), अतः (n=15)। पद संख्या निकालते समय अंत में (1) जोड़ना न भूलें।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (px+9y=45) और (20x+30y=103) का कोई हल न होने के लिए (p) का मान क्या होगा?

What is the value of (p) for the equations (px+9y=45) and (20x+30y=103) to have no solution?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

For no solution, (p/20=9/30) and (45/103) must be different. This gives (p=6).

Step 2

Why this answer is correct

The correct answer is B. (6). For no solution, (p/20=9/30) and (45/103) must be different. This gives (p=6).

Step 3

Exam Tip

कोई हल नहीं के लिए (p/20=9/30) और (45/103) अलग होना चाहिए। इससे (p=6) मिलता है।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (7x+11y=103) और (14x-11y=23) को हल करने पर (x) का मान क्या है?

Solving (7x+11y=103) and (14x-11y=23), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

Adding gives (21x=126), so (x=6). In such questions, one variable is eliminated immediately.

Step 2

Why this answer is correct

The correct answer is C. (6). Adding gives (21x=126), so (x=6). In such questions, one variable is eliminated immediately.

Step 3

Exam Tip

जोड़ने पर (21x=126), इसलिए (x=6)। ऐसे प्रश्नों में एक चर तुरंत समाप्त हो जाता है।

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Question Medium Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 44

\(103^2\) का मान क्या है?

What is the value of \(103^2\)?

Explanation opens after your attempt
Correct Answer

A. (10609)

Step 1

Concept

(1032=(100+3)2=10000+600+9=10609). Do not forget the middle term in ((a+b)2).

Step 2

Why this answer is correct

The correct answer is A. (10609). (1032=(100+3)2=10000+600+9=10609). Do not forget the middle term in ((a+b)2).

Step 3

Exam Tip

(1032=(100+3)2=10000+600+9=10609)। ((a+b)2) में मध्य पद न भूलें।

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Question Expert Mathematics Real Numbers Euclid’s Division Lemma Class 10 Level 1

यदि (a=59q+44), तो (a-103) को 59 से भाग देने पर शेषफल क्या होगा?

If (a=59q+44), what is the remainder when (a-103) is divided by 59?

Explanation opens after your attempt
Correct Answer

A. 0

Step 1

Concept

(a-103=59q+44-103=59q-59).

Step 2

Why this answer is correct

This can be written as (59(q-1)+0).

Step 3

Exam Tip

Therefore, the number is exactly divisible by 59 and the remainder is 0. चरण 1: (a-103=59q+44-103=59q-59)। चरण 2: इसे (59(q-1)+0) लिखा जा सकता है। चरण 3: इसलिए संख्या 59 से पूर्णतः विभाजित है और शेषफल 0 है।

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