Expert Chemistry Chapter 01: Solutions Class 12 Level 5

पाँच सौ मिलीलीटर शून्य दशमलव दो मोलर विलयन बनाने के लिए निर्जल सोडियम कार्बोनेट का कितना द्रव्यमान चाहिए?

What mass of anhydrous sodium carbonate is needed to prepare 500 mL of 0.2 M solution?

Explanation opens after your attempt
Correct Answer

B. 10.60 ग्राम / 10.60 g

Step 1

Concept

Required moles are 0.2 multiplied by 0.500 which equals 0.100 mol.

Step 2

Why this answer is correct

Molar mass of anhydrous sodium carbonate is 106 g mol−1.

Step 3

Exam Tip

Mass required is 0.100 multiplied by 106 which is 10.60 g. चरण 1: आवश्यक मोल शून्य दशमलव दो गुणा शून्य दशमलव पाँच यानी शून्य दशमलव एक हैं। चरण 2: निर्जल सोडियम कार्बोनेट का मोलर द्रव्यमान एक सौ छह ग्राम प्रति मोल है। चरण 3: द्रव्यमान शून्य दशमलव एक गुणा एक सौ छह यानी दस दशमलव छह ग्राम होगा।

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The correct answer is B. 10.60 ग्राम / 10.60 g.

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