What is the value of lim x→6 (x^2 - 36)/(x - 6)?
lim x→6 (x^2 - 36)/(x - 6) का मान क्या है?
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Correct Answer
D. 12
ExplanationStep 1: Factor the difference of squares. Step 2: x^2 - 36 = (x-6)(x+6); after cancellation, the limit is 6+6 = 12. Step 3: For 0/0 limits, factorization is often the fastest method.
Step 1: Difference of squares factor करें। Step 2: x^2 - 36 = (x-6)(x+6); cancel करने पर limit 6+6 = 12। Step 3: 0/0 form में factorization बहुत काम आता है।