What is the value of (3+4i)(1-2i)?
(3+4i)(1-2i) का मान क्या होगा?
Show answer and explanation
A. 11-2i / 11-2i
ExplanationStep 1: Use distributive law in complex multiplication. Step 2: 3-6i+4i-8i² = 3-2i+8 = 11-2i. Step 3: Use i²=-1 at the end.
Step 1: Complex multiplication में distributive law लगाएं। Step 2: 3-6i+4i-8i² = 3-2i+8 = 11-2i। Step 3: i²=-1 को अंत में use करें।