What is the slope of the tangent to y = x^2 at x = 11?
वक्र y = x^2 पर x = 11 पर tangent की slope क्या होगी?
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Correct Answer
A. 22
ExplanationStep 1: The slope of a tangent is found using the derivative. Step 2: dy/dx = 2x, so at x=11, slope = 2×11 = 22. Step 3: When slope is asked, find the derivative first.
Step 1: Tangent की slope derivative से मिलती है। Step 2: dy/dx = 2x, इसलिए x=11 पर slope = 2×11 = 22। Step 3: Slope पूछे तो पहले derivative निकालें।