What is the slope of normal to y=x²+5x at x=6?
y=x²+5x पर x=6 पर normal की slope क्या है?
Show answer and explanation
C. -1 / 17
ExplanationStep 1: Identify the concept: normal slope. Step 2: The tangent slope is m=17. Normal slope is -1/m=-1/17. Step 3: Exam tip: Normal slope is the negative reciprocal of tangent slope.
Step 1: अवधारणा normal slope है। Step 2: Tangent slope m=17 है। Normal slope -1/m=-1/17। Step 3: याद रखें: Normal slope tangent slope की negative reciprocal होती है।