A. y ≥ 7
ExplanationStep 1: The minimum value of x^2 is 0. Step 2: So the minimum value of x^2 + 7 is 7, hence y ≥ 7. Step 3: A quadratic x^2 + c opens upward.
Step 1: x^2 की सबसे छोटी value 0 होती है। Step 2: इसलिए x^2 + 7 की सबसे छोटी value 7 होगी, यानी y ≥ 7। Step 3: Quadratic x^2 + c ऊपर की ओर खुलता है।
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