C. y ≥ 5
ExplanationStep 1: The minimum value of x^2 is 0. Step 2: So the minimum value of x^2 + 5 is 5, hence y ≥ 5. Step 3: A quadratic x^2 + c opens upward.
Step 1: x^2 की सबसे छोटी value 0 होती है। Step 2: इसलिए x^2 + 5 की सबसे छोटी value 5 होगी, यानी y ≥ 5। Step 3: Quadratic x^2 + c ऊपर की ओर खुलता है।
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