B. y ≥ 0
ExplanationStep 1: The minimum value of x^2 is 0. Step 2: So the minimum value of x^2 + 0 is 0, hence y ≥ 0. Step 3: A quadratic x^2 + c opens upward.
Step 1: x^2 की सबसे छोटी value 0 होती है। Step 2: इसलिए x^2 + 0 की सबसे छोटी value 0 होगी, यानी y ≥ 0। Step 3: Quadratic x^2 + c ऊपर की ओर खुलता है।
Tap once to confirm. On the next tap, login will open for the answer.
Tap once to confirm. On the next tap, login will open for the answer.
Tap once to confirm. On the next tap, login will open for the answer.
Tap once to confirm. On the next tap, login will open for the answer.
Tap once to confirm. On the next tap, login will open for the answer.
Tap once to confirm. On the next tap, login will open for the answer.
Use Google login or mobile OTP. Admin can block users and control login providers.
Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.