What is the plane through (1, 1, 2) with normal vector (1, 1, 0)?
Point (1, 1, 2) से गुजरने और normal vector (1, 1, 0) वाले plane का equation क्या है?
Show answer and explanation
A. x+1y+(-2)=0
ExplanationStep 1: Identify the concept: plane equation. Step 2: The plane formula is A(x-x₁)+B(y-y₁)+C(z-z₁)=0. Substitution gives x+1y+(-2)=0. Step 3: Exam tip: The normal vector gives the coefficients of the plane.
Step 1: अवधारणा plane equation है। Step 2: Plane formula A(x-x₁)+B(y-y₁)+C(z-z₁)=0 है। Substitute करने पर x+1y+(-2)=0। Step 3: याद रखें: Normal vector plane के coefficients देता है।