What is the equation of the plane with normal vector (5,6,3) passing through point (5,2,2)?
Normal vector (5,6,3) और point (5,2,2) से गुजरने वाले plane का equation क्या है?
Show answer and explanation
Correct Answer
B. 5x+6y+3z-43=0
ExplanationStep 1: use plane formula n·(r-r0)=0. Step 2: substituting values gives 5(x-5)+6(y-2)+3(z-2)=0, i.e. 5x+6y+3z-43=0. Step 3: tip: the normal vector gives the plane coefficients.
Step 1: plane formula n·(r-r0)=0 use करें। Step 2: values रखने पर 5(x-5)+6(y-2)+3(z-2)=0, यानी 5x+6y+3z-43=0। Step 3: tip: normal vector plane के coefficients देता है।