What is the eccentricity of hyperbola x²/16 - y²/9 = 1?
hyperbola x²/16 - y²/9 = 1 की eccentricity क्या है?
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Correct Answer
C. 5/4 / 5/4
ExplanationStep 1: For the hyperbola a² = 16 and b² = 9. Step 2: e = √(1 + b²/a²) = √(1 + 9/16)=5/4. Step 3: Eccentricity of a hyperbola is greater than 1.
Step 1: hyperbola में a² = 16 और b² = 9 है। Step 2: e = √(1 + b²/a²) = √(1 + 9/16)=5/4। Step 3: hyperbola की eccentricity 1 से अधिक होती है।