What is the distance of point (3,1,2) from the plane 2x+3y+6z+(0)=0?
Point (3,1,2) की plane 2x+3y+6z+(0)=0 से distance क्या है?
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Correct Answer
C. 3
ExplanationStep 1: point-plane distance formula is |ax1+by1+cz1+d|/sqrt(a²+b²+c²). Step 2: denominator is sqrt(4+9+36)=7 and numerator is 21, so distance is 3. Step 3: tip: do not forget the absolute value in plane distance.
Step 1: point-plane distance formula |ax1+by1+cz1+d|/sqrt(a²+b²+c²) है। Step 2: denominator sqrt(4+9+36)=7 और numerator 21, इसलिए distance 3। Step 3: tip: plane distance में absolute value लेना न भूलें।