What is the distance of point (10,1,2) from the plane 2x+3y+6z+(-28)=0?
Point (10,1,2) की plane 2x+3y+6z+(-28)=0 से distance क्या है?
Show answer and explanation
Correct Answer
A. 1
ExplanationStep 1: point-plane distance formula is |ax1+by1+cz1+d|/sqrt(a²+b²+c²). Step 2: denominator is sqrt(4+9+36)=7 and numerator is 7, so distance is 1. Step 3: tip: do not forget the absolute value in plane distance.
Step 1: point-plane distance formula |ax1+by1+cz1+d|/sqrt(a²+b²+c²) है। Step 2: denominator sqrt(4+9+36)=7 और numerator 7, इसलिए distance 1। Step 3: tip: plane distance में absolute value लेना न भूलें।