What is the centre of circle (x-10)² + (y+5)² = 81?
वृत्त (x-10)² + (y+5)² = 81 का केंद्र क्या है?
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Correct Answer
C. (10 -5) / (10 -5)
ExplanationStep 1: Identify circle form (x-h)² + (y-k)² = r². Step 2: From x-10 h=10 and from y+5 k=-5. Step 3: Read signs in brackets oppositely.
Step 1: Circle form (x-h)² + (y-k)² = r² पहचानें। Step 2: x-10 से h=10 और y+5 से k=-5 है। Step 3: Bracket के signs उल्टे पढ़ें।