What is d/dx [sin^(-1)(12x)]?
d/dx [sin^(-1)(12x)] क्या है?
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Correct Answer
D. 12 / sqrt(1-144x^2)
ExplanationStep 1: derivative of sin^(-1)u is u'/sqrt(1-u^2). Step 2: here u=12x, so u'=12, answer 12/sqrt(1-144x^2). Step 3: tip: inverse sine derivative has a square-root denominator.
Step 1: derivative of sin^(-1)u = u'/sqrt(1-u^2)। Step 2: u=12x है इसलिए u'=12, answer 12/sqrt(1-144x^2)। Step 3: tip: inverse sine में denominator square root वाला होता है।