What area is given by ∫₀^{π/2} sinx dx?
∫₀^{π/2} sinx dx से मिलने वाला area क्या है?
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Correct Answer
B. 1
ExplanationStep 1: Identify definite integral area. Step 2: ∫sinx dx=-cosx, so [-cosx]₀^{π/2}=0-(-1)=1. Step 3: Exam tip: Remember standard trigonometric definite integrals.
Step 1: अवधारणा definite integral area है। Step 2: ∫sinx dx=-cosx, इसलिए [-cosx]₀^{π/2}=0-(-1)=1। Step 3: Exam note: standard trig definite integrals याद रखें।