Easy Math Class 9 Level 10

In an isosceles triangle the vertex angle is 90° then what is each base angle?

समद्विबाहु त्रिभुज में शीर्ष कोण 90° है तो प्रत्येक आधार कोण कितना होगा?

A) 30° / 30° B) 45° / 45° C) 60° / 60° D) 90° / 90°
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Correct Answer

B. 45° / 45°

Explanation

The remaining equal base angles sum to 90° so each is 45°.

शेष दो बराबर आधार कोणों का योग 90° है इसलिए प्रत्येक 45° होगा।

Related Questions

Easy Math Class 10 Level 1

What is the area of a circle with radius 7 cm when π = 22/7?

7 सेमी त्रिज्या वाले वृत्त का क्षेत्रफल कितना होगा जब π = 22/7 हो?

A. 44 सेमी² / 44 cm² B. 77 सेमी² / 77 cm² C. 154 सेमी² / 154 cm² D. 308 सेमी² / 308 cm²
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