Easy Chemistry Chapter 01: Solutions Class 12 Level 6

1 किलोग्राम जल में 3 मिलीग्राम फ्लोराइड हो तो सांद्रता लगभग कितनी पीपीएम होगी?

If 1 kg water contains 3 mg fluoride, what is the approximate concentration in ppm?

Explanation opens after your attempt
Correct Answer

A. 3 पीपीएम / 3 ppm

Step 1

Concept

1 kg water is about one million mg.

Step 2

Why this answer is correct

3 mg per one million mg = 3 ppm.

Step 3

Exam Tip

For water samples, mg per kg quickly gives ppm. चरण 1: 1 किलोग्राम जल लगभग 10 लाख मिलीग्राम होता है। चरण 2: 3 मिलीग्राम प्रति 10 लाख मिलीग्राम = 3 पीपीएम। चरण 3: जल नमूनों में मिलीग्राम प्रति किलोग्राम से पीपीएम जल्दी मिलता है।

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