For y=x^12, at x=13 and dx=0.01, what is the approximate dy?
y=x^12 में x=13 पर dx=0.01 हो, तो approximate dy क्या होगा?
Show answer and explanation
A. 5376481182111 / 25
ExplanationStep 1: in differentials, dy≈f'(x)dx. Step 2: f'(x)=12x^11; substituting x=13 and dx=0.01 gives dy≈5376481182111/25. Step 3: tip: for small change, use derivative × change.
Step 1: differentials में dy≈f'(x)dx होता है। Step 2: f'(x)=12x^11; x=13 और dx=0.01 रखने पर dy≈5376481182111/25। Step 3: tip: small change questions में derivative × change use करें।