For x=t², y=t³, what is dy/dx at t=6?
x=t², y=t³ के लिए dy/dx at t=6 क्या है?
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Correct Answer
A. 9
ExplanationStep 1: Identify the concept: parametric differentiation. Step 2: dy/dx=(dy/dt)/(dx/dt)=3t²/2t=3t/2. At t=6, it is 9. Step 3: Exam tip: In parametric form, take the ratio of derivatives.
Step 1: अवधारणा parametric differentiation है। Step 2: dy/dx=(dy/dt)/(dx/dt)=3t²/2t=3t/2। t=6 पर 9। Step 3: याद रखें: Parametric form में derivatives का ratio लें।