For parametric curve x=t^2, y=t^3, what is the slope dy/dx at parameter t=10?
Parametric curve x=t^2, y=t^3 पर parameter t=10 के लिए tangent की slope dy/dx क्या है?
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Correct Answer
D. 15
ExplanationStep 1: parametric slope is dy/dx=(dy/dt)/(dx/dt). Step 2: dy/dt=3t^2 and dx/dt=2t, so slope=3t/2=15. Step 3: tip: in parametric questions, use ratio of derivatives.
Step 1: parametric slope dy/dx=(dy/dt)/(dx/dt) है। Step 2: dy/dt=3t^2 और dx/dt=2t, इसलिए slope=3t/2=15। Step 3: tip: parametric questions में direct y/x नहीं, derivatives का ratio लें।