Hard Chemistry Chapter 01: Solutions Class 12 Level 6

11.7 ग्राम सोडियम क्लोराइड को 400 ग्राम जल में घोला गया। विलयन की मोललता कितनी होगी?

11.7 g sodium chloride is dissolved in 400 g water. What is the molality of the solution?

Explanation opens after your attempt
Correct Answer

B. 0.50 मोल प्रति किलोग्राम / 0.50 mol kg-1

Step 1

Concept

Moles of sodium chloride = 11.7 ÷ 58.5 = 0.2.

Step 2

Why this answer is correct

Water = 400 g = 0.4 kg. Molality = 0.2 ÷ 0.4 = 0.50 mol kg^-1.

Step 3

Exam Tip

Keep only kilogram mass of solvent in the denominator. चरण 1: सोडियम क्लोराइड के मोल = ११.७ ÷ ५८.५ = ०.२। चरण 2: जल = ४०० ग्राम = ०.४ किलोग्राम। मोललता = ०.२ ÷ ०.४ = ०.५० मोल प्रति किलोग्राम। चरण 3: हर में विलायक का किलोग्राम द्रव्यमान ही रखें।

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The correct answer is B. 0.50 मोल प्रति किलोग्राम / 0.50 mol kg-1.

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